Two polaroids are placed in the path of an un | vedclass

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(A) $1$. Initially,the unpolarized light of intensity $I_0$ passes through the first polaroid. The intensity of light emerging from the first polaroid

Vedclass · Accepted Answer

$\left( \frac{I_0}{8} ight) \sin^2(2	heta)$

Vedclass · Answer

(A) $1$. Initially,the unpolarized light of intensity $I_0$ passes through the first polaroid. The intensity of light emerging from the first polaroid is $I_1 = \frac{I_0}{2}$.$2$. The second polaroid is placed such that no light emerges from it,meaning the first and second polaroids are crossed (angle between them is $90^\circ$).$3$. $A$ third polaroid is placed between them at an angle $	heta$ with the first polaroid. The angle between the third and second polaroid is $(90^\circ - 	heta)$.$4$. Intensity after the third polaroid: $I_2 = I_1 \cos^2(	heta) = \frac{I_0}{2} \cos^2(	heta)$.$5$. Intensity after the second (last) polaroid: $I_3 = I_2 \cos^2(90^\circ - 	heta) = I_2 \sin^2(	heta)$.$6$. Substituting $I_2$: $I_3 = \left( \frac{I_0}{2} \cos^2(	heta) ight) \sin^2(	heta) = \frac{I_0}{2} (\sin(	heta)\cos(	heta))^2 = \frac{I_0}{2} \left( \frac{\sin(2	heta)}{2} ight)^2 = \frac{I_0}{8} \sin^2(2	heta)$.

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